Power Optimizer
M500/14

Looking at the electrotechnical situation at optimal lighting conditions, it can be seen that one module in the example can produce 400W. There is a voltage of 40V at each module and a current of 10A in the entire system.

However, if shading affects the module, the power drops accordingly. In our example (see below), the shading is 50%, so the current drops to 5A. As the current decreases, the power also decreases:

P (power) = U (voltage) * I (current)

Because all modules are connected in series in a string, the current at all modules is now only 5A. The reason for this is the behaviour of the current in a series connection:

| _total = |₁=|₂=…

The formula shows that the electrical current is the same at every point in the circuit, i.e. the current is determined by the weakest module. In this case, Itotal is therefore 5A.

Modern inverters can circumvent this problem by activating the bypass diodes inside the modules. These bypass diodes disconnect the problematic module from the string by acting as a “bypass” for the current. The current of the string is then conducted via the diode itself and not via the module. However, the problem arises here that the uncoupled module continues to produce current. Since the energy can no longer be fed into the system, it is released in heat and causes so-called hot spots. These hot spots can damage or even destroy the module.

Using the BRC Power Optimizer prevents all these problems.

The Power Optimizer is connected in parallel to the module. In case of shading, it is automatically activated by the inverter. Our technology makes it possible to change the relationship between voltage and current at the module. The voltage is summed up in a series connection, but the current is the same everywhere. Since we have a deficit in current in the example, the electrical current of all other modules in the string is attenuated. To prevent this, the interconnected BRC Power Optimizer converts modules voltage and current into a different voltage and current based on the inverters demanded string current.

In the example, it would make 5A and 40V ⟶ 10A and 20V. The result is that the total current everywhere in the string is now 10A again and each module can provide 10A. Although the voltage at the partially shaded module has become lower, this does not affect the voltage of the other modules.

| _total = |₁=|₂=…

U _total = U₁+U₂+…

The energy yield is maximized. The problem of hot spots is also solved, as all the energy flows into the system with the help of our Power Optimizer and is not lost in heat energy.